College Algebra (Abridged)

Solution: First, determine the value of ( − 2) , then take this value and substitute it into ( ) . ( ) = | − 7| ( − 2) = | − 2 − 7| = | − 9| = 9 Now, ( ) = + 5 , so by substituting = 9 , we get: (9) = 9 + 5 = 14 Question 3: B Solution: Solving the above quadratic equation, use the formula: = − ± √ 2 − 4 2 Where, = 1 , = − 3 and = − 10 . Substituting the values in above formula, we get: = − ( − 3) ± � ( − 3) 2 − 4(1)( − 10) 2(1) = 3 ± √ 49 2 = 3 ± 7 2 3+7 2 = 10 2 = 5 and 3−7 2 = − 4 2 = − 2 Question 4: D Solution: Solve −2 −1 = +4 ( 2 +2 ) using cross-multiplication. ( − 2)(2 + 2) = ( − 1)( + 4) 2 2 − 2 − 4 = 2 + 3 − 4 2 − 5 = 0 ( − 5) = 0 Therefore, = 0 and = 5 Question 5 : A

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