College Math

Solution: Let us find the slopes of both the lines. 2x – 4y = 3 y = (2x – 3)/4 y = x/2 -3/4 Slope of first line = ½ 2x + 4y = -3 y = (–3 – 2x)/4 y = –3/4 –x/2 Slope of second line is – ½ Since the slopes are neither equal, nor reciprocal (are opposite) to each other, they are neither parallel nor perpendicular to each other. Hence, option d is true. 5. c Solution: We find the slope of the given line. 2x + 4y = -1 y = (-1 – 2x)/4 y = -1/4 – x/2 The slope of the line is -1/2. The slope for the line perpendicular to this given line would be 2 (opposite reciprocal) Substituting the values of x-intercept = -1, y-intercept at 3 and slope m = 2 in point-slope form , we get the following equation: (y – 3) = 2(x + 1) y – 3 = 2x + 2 2x – y = –5 is the desired equation 6. c

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