Statistics

Statistics

A.3 Homework Set Solutions

1. See below. a. Yes b. No c. Yes d. No 2. See below.

3.

= ( ) = 1.5

4. See below.

a. Mean: 2.43 b. Variance: 1.97 c. Standard Deviation: 1.40

( = 3) = 0.0512 ≈ 5%

5.

a. Continuous b. Continuous c. Discrete d. Continuous e. Continuous

6. See below.

a. Mean: 2 b. Variance: 1 c. Standard Deviation

A.5 Homework Set Solutions

A.4 Homework Set Solutions

1. See below.

(0 ≤ < 0.56) = 0.2123 ( > 0.23) = 0.4090 ( ≤ −1.92) = 0.9726

1. 2. 3. 4.

a. (66.1, 82.35) b. It would be highly unlikely,

since this is far larger than the average of 74.22 minutes, as shown by the confidence interval.

(−1.43 > ) = 0.0764 5. 1 = 68%, 2 = 95%,

and

3 =

99.77% 6. See below.

2. (2.81, 2.91) 3. (86.9, 103.1) 4. (0.096, 0.144)

a. 0.0049 b. 0.1624 c. 0.7486

A.6 Homework Set Solutions

1. See below. a.

0 : = 69.21 : ≠ 69.21

b.

2.

/2 = ±1.96

68.43−69.21 3.72 √30

3.

=

≈ −7.04

4.

≤ 2 ⟹ −7.04 ≤ −1.96 Reject the null hypothesis. There is enough evidence to reject the claim that the average cost of a hotel stay in Atlanta is $69.21.

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